0=-4.9t^2-33.6t-4.9

Solution for 0=-4.9t^2-33.6t-4.9 equation:

0=-4.9t^2-33.6t-4.9

We move all terms to the left:

0-(-4.9t^2-33.6t-4.9)=0

We add all the numbers together, and all the variables

-(-4.9t^2-33.6t-4.9)=0

We get rid of parentheses

4.9t^2+33.6t+4.9=0

a = 4.9; b = 33.6; c = +4.9;
Δ = b2-4ac
Δ = 33.62-4·4.9·4.9
Δ = 1032.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33.6)-\sqrt{1032.92}}{2*4.9}=\frac{-33.6-\sqrt{1032.92}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33.6)+\sqrt{1032.92}}{2*4.9}=\frac{-33.6+\sqrt{1032.92}}{9.8}
$